Two genomes over the same set of gene families form a canonical pair when each of them has exactly one gene from each family. Different distances of canonical genomes can be derived from a structure called breakpoint graph, which represents the relation between the two given genomes as a collection of cycles of even length and paths. Then, the breakpoint distance is equal to n - (c_2 + p_0/2), where n is the number of genes, c_2 is the number of cycles of length 2 and p_0 is the number of paths of length 0. Similarly, when the considered rearrangements are those modeled by the double-cut-and-join (DCJ) operation, the rearrangement distance is n - (c + p_e/2), where c is the total number of cycles and p_e is the total number of even paths. The distance formulation is a basic unit for several other combinatorial problems related to genome evolution and ancestral reconstruction, such as median or double distance. Interestingly, both median and double distance problems can be solved in polynomial time for the breakpoint distance, while they are NP-hard for the rearrangement distance. One way of exploring the complexity space between these two extremes is to consider the {\sigma}_k distance, defined to be n - [c_2 + c_4 + ... + c_k + (p_0 + p_2 + ... +p_k)/2], and increasingly investigate the complexities of median and double distance for the {\sigma}_4 distance, then the {\sigma}_6 distance, and so on. While for the median much effort was done in our and in other research groups but no progress was obtained even for the {\sigma}_4 distance, for solving the double distance under {\sigma}_4 and {\sigma}_6 distances we could devise linear time algorithms, which we present here.
翻译:在同一组基因组中, 两个基因组的基因组组成了一条康乃馨配对, 每个基因组都有一个完全来自每个家族的基因。 不同的卡诺基因组的距离可以从一个叫做断点图的结构中得出, 这代表了两个给定基因组之间的关系, 是一个连长和路径周期的集合。 然后, 断点距离等于 n - (c_ 2 + p_ 0/2), 其中n 是基因进化和祖传重建中, c_ 2 的周期数, p_ 0 是长度的路径数 。 同样, 当考虑的调整是双开点和join( DCJ) 操作所建的距离 。 重新排列距离是 n - (c + p_e/2), 其中c 是周期和 p_ 路径的总数 。 距离配方是一个基本单位, 与基因进化和祖传重建有关的若干其他组合问题, 比如中位或双距离。 有意思的是, 中位和双距离问题都可以在多位时间段时间段里解决 。 。 中位和双位的中位和双距离问题可以在多时间段时间段里解决, 然后在断点的距离上, 。</s>