Two genomes over the same set of gene families form a canonical pair when each of them has exactly one gene from each family. Different distances of canonical genomes can be derived from a structure called breakpoint graph, which represents the relation between the two given genomes as a collection of cycles of even length and paths. Then, the breakpoint distance is equal to n - (c_2 + p_0/2), where n is the number of genes, c_2 is the number of cycles of length 2 and p_0 is the number of paths of length 0. Similarly, when the considered rearrangements are those modeled by the double-cut-and-join (DCJ) operation, the rearrangement distance is n - (c + p_e/2), where c is the total number of cycles and p_e is the total number of even paths. The distance formulation is a basic unit for several other combinatorial problems related to genome evolution and ancestral reconstruction, such as median or double distance. Interestingly, both median and double distance problems can be solved in polynomial time for the breakpoint distance, while they are NP-hard for the rearrangement distance. One way of exploring the complexity space between these two extremes is to consider the {\sigma}_k distance, defined to be n - [c_2 + c_4 + ... + c_k + (p_0 + p_2 + ... +p_k)/2], and increasingly investigate the complexities of median and double distance for the {\sigma}_4 distance, then the {\sigma}_6 distance, and so on. While for the median much effort was done in our and in other research groups but no progress was obtained even for the {\sigma}_4 distance, for solving the double distance under {\sigma}_4 and {\sigma}_6 distances we could devise linear time algorithms, which we present here.
翻译:通过一种称为断点图的结构,可以从具有相同基因家族集合的两个基因组中派生出不同的规范化距离,当其中每个基因组都恰好具有一个家族中的基因时,它们形成一个规范化对。断点距离等于n - (c_2 + p_0/2),其中n是基因数量,c_2是长度为2的循环数,p_0是长度为0的路径数。同样,当考虑的重组由双切和连接(DCJ)操作建模时,重新排列距离为n - (c + p_e/2),其中c是循环总数,p_e是偶数路径的总数。距离制定为与基因组演化和祖先重建相关的其他组合问题的基本单位,例如中位数或双距。有趣的是,尽管对于断点距离,中位数和双距问题都可以在多项式时间内解决,但对于重新排列距离而言,它们是NP-hard的。探索这两个极端之间的复杂空间的一种方法是考虑{\sigma}_k距离,定义为n - [c_2 + c_4 + ...+ c_k + (p_0 + p_2 +...+ p_k)/2] ,并逐渐研究{\sigma}_4距离,然后是{\sigma}_6距离等。虽然针对中位数,在我们和其他研究小组中都做出了很大努力,但即使对于{\sigma}_4距离也没有取得任何进展,但我们可以设计出线性时间算法来解决{\sigma}_4和{\sigma}_6距离下的双距问题,我们在此呈现。