We give reconstruction algorithms for subclasses of depth-3 arithmetic circuits. In particular, we obtain the first efficient algorithm for finding tensor rank, and an optimal tensor decomposition as a sum of rank-one tensors, when given black-box access to a tensor of super-constant rank. We obtain the following results: 1. A deterministic algorithm that reconstructs polynomials computed by $\Sigma^{[k]}\bigwedge^{[d]}\Sigma$ circuits in time $\mathsf{poly}(n,d,c) \cdot \mathsf{poly}(k)^{k^{k^{10}}}$ 2. A randomized algorithm that reconstructs polynomials computed by multilinear $\Sigma^{k]}\prod^{[d]}\Sigma$ circuits in time $\mathsf{poly}(n,d,c) \cdot k^{k^{k^{k^{O(k)}}}}$ 3. A randomized algorithm that reconstructs polynomials computed by set-multilinear $\Sigma^{k]}\prod^{[d]}\Sigma$ circuits in time $\mathsf{poly}(n,d,c) \cdot k^{k^{k^{k^{O(k)}}}}$, where $c=\log q$ if $\mathbb{F}=\mathbb{F}_q$ is a finite field, and $c$ equals the maximum bit complexity of any coefficient of $f$ if $\mathbb{F}$ is infinite. Prior to our work, polynomial time algorithms for the case when the rank, $k$, is constant, were given by Bhargava, Saraf and Volkovich [BSV21]. Another contribution of this work is correcting an error from a paper of Karnin and Shpilka [KS09] that affected Theorem 1.6 of [BSV21]. Consequently, the results of [KS09, BSV21] continue to hold, with a slightly worse setting of parameters. For fixing the error we study the relation between syntactic and semantic ranks of $\Sigma\Pi\Sigma$ circuits. We obtain our improvement by introducing a technique for learning rank preserving coordinate-subspaces. [KS09] and [BSV21] tried all choices of finding the "correct" coordinates, which led to having a fast growing function of $k$ at the exponent of $n$. We find these spaces in time that is growing fast with $k$, yet it is only a fixed polynomial in $n$.
翻译:我们为深度-3 计算电路的亚类提供重建算法 。 特别是, 当给予黑盒访问超级等级时, 我们获取了第一个找到 AR0 级的高效算法 。 当给定黑盒访问超级等级时, 我们获得以下结果 : 1. 一种用 $\ sigma\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\