Consider a random access communication scenario over a channel whose operation is defined for any number of possible transmitters. As in the model recently introduced by Polyanskiy for the Multiple Access Channel (MAC) with a fixed, known number of transmitters, the channel is assumed to be invariant to permutations on its inputs, and all active transmitters employ identical encoders. Unlike the Polyanskiy model, in the proposed scenario, neither the transmitters nor the receiver knows which transmitters are active. We refer to this agnostic communication setup as the Random Access Channel (RAC). Scheduled feedback of a finite number of bits is used to synchronize the transmitters. The decoder is tasked with determining from the channel output the number of active transmitters, $k$, and their messages but not which transmitter sent which message. The decoding procedure occurs at a time $n_t$ depending on the decoder's estimate, $t$, of the number of active transmitters, $k$, thereby achieving a rate that varies with the number of active transmitters. Single-bit feedback at each time $n_i, i \leq t$, enables all transmitters to determine the end of one coding epoch and the start of the next. The central result of this work demonstrates the achievability on a RAC of performance that is first-order optimal for the MAC in operation during each coding epoch. While prior multiple access schemes for a fixed number of transmitters require $2^k - 1$ simultaneous threshold rules, the proposed scheme uses a single threshold rule and achieves the same dispersion.
翻译:考虑一个频道的随机访问通信方案, 该频道的运行是针对任何数量可能的同步发报机。 正如Polyanskiy最近为多存取频道(MAC)引入的模型一样, 多存取频道(MAC)使用一个固定的已知发报机数量, 该频道被假定不易改变其输入量, 所有活动发报机都使用相同的编码器。 与Polyanskiy模式不同的是, 在拟议设想中, 发报机和接收机都不知晓哪个发报机是活跃的。 我们将这个不可知通讯设置称为随机存取频道(RAC) 。 定时数的有限比特数反馈用于同步发报机。 解器的任务是从频道输出中确定活动发报机的数量, $k$, 和所有发报机发送机发送电的顺序。 解码程序在某时间进行, 取决于解码器的估算值, $t, 美元, 使用随机存取的频率, 从而得出主动发报发报机数量的不同比率。 每次单比回反馈, 每个时间 美元 开始运行规则的频率, 开始计算, 开始一个正常运行, 开始运行的频率 。