We study the problem of recovering the common $k$-sized support of a set of $n$ samples of dimension $d$, using $m$ noisy linear measurements per sample. Most prior work has focused on the case when $m$ exceeds $k$, in which case $n$ of the order $(k/m)\log(d/k)$ is both necessary and sufficient. Thus, in this regime, only the total number of measurements across the samples matter, and there is not much benefit in getting more than $k$ measurements per sample. In the measurement-constrained regime where we have access to fewer than $k$ measurements per sample, we show an upper bound of $O((k^{2}/m^{2})\log d)$ on the sample complexity for successful support recovery when $m\ge 2\log d$. Along with the lower bound from our previous work, this shows a sharp phase transition for the sample complexity of this problem around $k/m=1$. In fact, our proposed algorithm is sample-optimal in both the regimes. It follows that, in the $m\ll k$ regime, multiple measurements from the same sample are more valuable than measurements from different samples.
翻译:我们研究的是利用每份抽样的噪音线性测量数据,以美元为单位,回收一组维度样本的通用美元规模支持美元美元美元(美元)的问题,大多数先前工作的重点是当美元超过美元(美元)时的抽样复杂性为美元(k/m)\log(d/k)美元,在这种情况下,如果按美元(k/m)\log(k)美元(d/k)美元顺序(美元)为单位,则既必要又足够,因此,在这一制度中,只有各抽样事项的测量总数,而每份样本获得超过美元(k)美元测量数据没有多大好处。在每份抽样中,我们提议的测量算法都是抽取不到美元(k)美元的测量数据的受限制制度,因此,在每份样本中,从贵重的测量数据中,从不同样本的多个测量数据中得出。