In this article we compute analytically the number of Nash Equilibria (NE) for a two-choice game played on a (circular) ladder graph with $2n$ players. We consider a set of games with generic payoff parameters, with the only requirement that a NE occurs if the players choose opposite strategies (anti-coordination game). The results show that for both, the ladder and circular ladder, the number of NE grows exponentially with (half) the number of players $n$, as $N_{NE}(2n)\sim C(\varphi)^n$, where $\varphi=1.618..$ is the golden ratio and $C_{circ}>C_{ladder}$. In addition, the value of the scaling factor $C_{ladder}$ depends on the value of the payoff parameters. However, that is no longer true for the circular ladder (3-degree graph), that is $C_{circ}$ is constant, which might suggest that the topology of the graph indeed plays an important role for setting the number of NE.
翻译:在文章中,我们用分析方式计算出Nash Equilibria(NE)的数字,用于在(circ)阶梯图上用$2n美元玩的双选游戏。我们考虑的是一套具有通用报酬参数的游戏,唯一要求是当玩家选择相反的战略(反协调游戏)时,NE就会出现。结果显示,对于这两个游戏来说,梯子和圆梯子,NE的数量会随着玩家数目(一半)美元(即$N ⁇ NE}(2n)\sim C(varphi)n$($=1.618.美元)而指数确实在确定NE数量方面起着重要作用。此外,对于圆梯子(3度图)来说,这一点已不再如此。