One possibility of defining a quantum R\'enyi $\alpha$-divergence of two quantum states is to optimize the classical R\'enyi $\alpha$-divergence of their post-measurement probability distributions over all possible measurements (measured R\'enyi divergence), and maybe regularize these quantities over multiple copies of the two states (regularized measured R\'enyi $\alpha$-divergence). A key observation behind the theorem for the strong converse exponent of asymptotic binary quantum state discrimination is that the regularized measured R\'enyi $\alpha$-divergence coincides with the sandwiched R\'enyi $\alpha$-divergence when $\alpha>1$. Moreover, it also follows from the same theorem that to achieve this, it is sufficient to consider $2$-outcome measurements (tests) for any number of copies (this is somewhat surprising, as achieving the measured R\'enyi $\alpha$-divergence for $n$ copies might require a number of measurement outcomes that diverges in $n$, in general). In view of this, it seems natural to expect the same when $\alpha<1$; however, we show that this is not the case. In fact, we show that even for commuting states (classical case) the regularized quantity attainable using $2$-outcome measurements is in general strictly smaller than the R\'enyi $\alpha$-divergence (which is unique in the classical case). In the general quantum case this shows that the above "regularized test-measured" R\'enyi $\alpha$-divergence is not even a quantum extension of the classical R\'enyi divergence when $\alpha<1$, in sharp contrast to the $\alpha>1$ case.
翻译:定义两个量子的R\'enyi $\ alpha1 $-diverence 的可能性之一,就是优化传统的R\'enyi $\ alpha$-diverence R\ enyi $\ alphay = enyi $\ alpha$- digence, 在所有可能的测量(测量R\'enyi $\ enyi $\ alphay $\ alpha$\ diverence ) 上, 并可能使这些数量在两个州多份(常规测量R\ enyi $\ alphay $\ a difference) 中(正常的R\ enyy $$ $ $_ alpha- divation = divations) 的正反调中, 一个关键点是, 当常规的Rey $ 美元 美元 = 美元 美元 的正反向, 直值显示一个直径的直径直径直径, 直到直径直径直径直径, 直到直到直到直到直到直數。