We consider the problem of recovering an orthogonally decomposable tensor with a subset of elements distorted by noise with arbitrarily large magnitude. We focus on the particular case where each mode in the decomposition is corrupted by noise vectors with components that are correlated locally, i.e., with nearby components. We show that this deterministic tensor completion problem has the unusual property that it can be solved in polynomial time if the rank of the tensor is sufficiently large. This is the polar opposite of the low-rank assumptions of typical low-rank tensor and matrix completion settings. We show that our problem can be solved through a system of coupled Sylvester-like equations and show how to accelerate their solution by an alternating solver. This enables recovery even with a substantial number of missing entries, for instance for $n$-dimensional tensors of rank $n$ with up to $40\%$ missing entries.
翻译:我们考虑的是恢复一个可分解的螺旋状粒子的问题,其部分元素被噪声扭曲,其数量之大被任意扭曲。我们关注的是每种分解方式都因与本地相关部件(即附近部件)的噪声矢量而受腐蚀的特定情况。我们表明,这种决定性稀释完成问题具有非同寻常的特性,如果高压等级足够大,它可以在多元时间解决。这是典型的低压阵列和矩阵完成设置的低等级假设的极点。我们表明,我们的问题可以通过一个与Sylvester相似的方程式相结合的系统来解决,并展示如何通过交替的求解器加速解决问题。这样即使大量缺失的条目,例如,以美元为单位的单位数的单位反射器,但缺少的条目高达40美元。