Stacking is an important process within logistics. Some notable examples of items to be stacked are steel bars or steel plates in a steel yard or containers in a container terminal or on a ship. We say that two items are conflicting if their storage time intervals overlap in which case one of the items needs to be rehandled if the items are stored at the same LIFO storage location. We consider the problem of stacking items using $k$ LIFO locations with a minimum number of conflicts between items sharing a location. We present an extremely simple online stacking algorithm that is oblivious to the storage time intervals and storage locations of all other items when it picks a storage location for an item. The risk of assigning the same storage location to two conflicting items is proved to be of the order $1/k^2$ under mild assumptions on the distribution of the storage time intervals for the items. Intuitively, it seems natural to pick a storage location uniformly at random in the oblivious setting implying a risk of $1/k$ so the risk for our algorithm is surprisingly low. Our results can also be expressed within the context of the MAX $k$-CUT problem for circle graphs. The results indicate that circle graphs on average have relatively big $k$-cuts compared to the total number of edges.
翻译:堆叠是物流中的一个重要过程。要堆放的物品有钢条或钢板钢板或钢板,或集装箱码头或船上的容器。我们说,如果两件物品的储存时间间隔重叠,其中一件需要重新处理,如果物品储存在同一LIFO储存地点,则需要重新处理。我们考虑的是使用美元LIFO地点堆放物品的问题,在同一个地点的物品之间有最低数目的冲突;我们提出了一个非常简单的在线堆放算法,在所有其他物品的储存时间间隔和储存地点选择物品的储存地点时,这种算法不为人所知。如果将同一存放地点分配给两个互相冲突的物品,那么根据关于物品储存时间间隔分配的轻度假设,则需要重新处理其中一件物品。我们直觉地认为,在不明位置上任意选择一个储存地点似乎很自然,意味着有1美元/k美元的风险,因此我们的算法的风险非常低。我们的结果也可以在MAX美元-美元-CUT平面图中的平均比例图显示数字与大圆形图相比的结果。