We consider the $\varepsilon$-Consensus-Halving problem, in which a set of heterogeneous agents aim at dividing a continuous resource into two (not necessarily contiguous) portions that all of them simultaneously consider to be of approximately the same value (up to $\varepsilon$). This problem was recently shown to be PPA-complete, for $n$ agents and $n$ cuts, even for very simple valuation functions. In a quest to understand the root of the complexity of the problem, we consider the setting where there is only a constant number of agents, and we consider both the computational complexity and the query complexity of the problem. For agents with monotone valuation functions, we show a dichotomy: for two agents the problem is polynomial-time solvable, whereas for three or more agents it becomes PPA-complete. Similarly, we show that for two monotone agents the problem can be solved with polynomially-many queries, whereas for three or more agents, we provide exponential query complexity lower bounds. These results are enabled via an interesting connection to a monotone Borsuk-Ulam problem, which may be of independent interest. For agents with general valuations, we show that the problem is PPA-complete and admits exponential query complexity lower bounds, even for two agents.
翻译:我们考虑的是美元(varepsilon$-consensus-calming)问题,其中一组不同物剂旨在将连续的资源分成两个(不一定毗连的)部分,所有物剂都同时认为这两个部分的价值大致相同(最高为$varepsilon$ )。这个问题最近被证明为PPPA的完整,对于一元和零减,甚至对于非常简单的估价功能。为了了解问题的复杂性的根源,我们考虑的是只有固定数量的物剂的设置,我们考虑的是问题的计算复杂性和质询复杂性。对于具有单调调值的物剂,我们显示了一种二分法:对于两个物剂,问题在于多调时溶胶溶剂,而对于三个或三个以上物剂,则在于PPPA的完整。同样,我们表明,对于两种单调质制剂,问题可以通过多调式的质谱质质质查询来解决,而对于三个或更多物剂,我们提供指数质查询的复杂度则较低界限。这些结果可以通过一个有趣的连连连线连接到一个单调的Bors-PA的物剂的复杂度问题,而我们又能显示两种不同的指数化的复杂度问题。