There is a random variable (X) with a determined outcome (i.e., X = x0), p(x0) = 1. Consider x0 to have a discrete uniform distribution over the integer interval [1, s], where the size of the sample space (s) = 1, in the initial state, such that p(x0) = 1. What is the probability of x0 and the associated information entropy (H), as s increases exponentially? If the sample space expansion occurs at an exponential rate (rate constant = lambda) with time (t) and applying time scaling, such that T = lambda x t, gives: p(x0|T)=exp(-T) and H(T)=T. The characterization has also been extended to include exponential expansion by means of simultaneous, independent processes, as well as the more general multi-exponential case. The methodology was applied to the expansion of the broad money supply of US$ over the period 2001-2019, as a real-world example. At any given time, the information entropy is related to the rate at which the sample space is expanding. In the context of the expansion of the broad money supply, the information entropy could be considered to be related to the "velocity" of the expansion of the money supply.
翻译:有一个随机变量(X),其结果确定(即,X=x0,p(x0)=1. 考虑x0,在整数间隔[1,s]上有一个离散的统一分布,在初始状态中,样本空间的大小(s)=1,例如p(x0)=1,p(x0)=1. 当X指数增长时,x0的概率和相关信息倍增(H)的概率是多少?如果样本空间扩张以指数速率(恒定值=lambda)发生,时间(t)并适用时间缩放,例如T= lambdaxt,提供:p(x0)-T)=exp(-T)=exp(-T)=T=T。特征还扩大到包括以同步、独立程序以及更一般的多解释性案例的方式指数扩张。该方法适用于2001-2019年期间扩大美元的广泛货币供应量,作为真实世界的一个例子。在任何特定时间,该信息均与样本扩张速度有关,即与样本供应的扩展速度有关。