For a drawing of a labeled graph, the rotation of a vertex or crossing is the cyclic order of its incident edges, represented by the labels of their other endpoints. The extended rotation system (ERS) of the drawing is the collection of the rotations of all vertices and crossings. A drawing is simple if each pair of edges has at most one common point. Gioan's Theorem states that for any two simple drawings of the complete graph $K_n$ with the same crossing edge pairs, one drawing can be transformed into the other by a sequence of triangle flips (a.k.a. Reidemeister moves of Type 3). This operation refers to the act of moving one edge of a triangular cell formed by three pairwise crossing edges over the opposite crossing of the cell, via a local transformation. We investigate to what extent Gioan-type theorems can be obtained for wider classes of graphs. A necessary (but in general not sufficient) condition for two drawings of a graph to be transformable into each other by a sequence of triangle flips is that they have the same ERS. As our main result, we show that for the large class of complete multipartite graphs, this necessary condition is in fact also sufficient. We present two different proofs of this result, one of which is shorter, while the other one yields a polynomial time algorithm for which the number of needed triangle flips for graphs on $n$ vertices is bounded by $O(n^{16})$. The latter proof uses a Carath\'eodory-type theorem for simple drawings of complete multipartite graphs, which we believe to be of independent interest. Moreover, we show that our Gioan-type theorem for complete multipartite graphs is essentially tight in the sense that having the same ERS does not remain sufficient when removing or adding very few edges.
翻译:标签图形的绘图, 顶端或交叉点的旋转是其事件边缘的循环顺序, 以其他端点的标签为代表。 延长的旋转系统( ERS) 是收集所有顶端和交叉点的旋转。 如果每对边缘都有一个最常见的点, 绘图很简单 。 Gioan 的“ 理论” 表示, 完整图形中的任何两张简单的绘图 $K_ n$ 与同一直径边对齐, 一个绘图可以由三角形翻转序列( a. k. a. Reidemeister 3 类型) 转换成另一个。 这个操作指的是将三角形的边缘之一移动, 由三个对对齐的横跨端组成, 通过本地变换。 我们调查Gioan 型的“ 论” 是否能够为更广大的图形类别获得相同的结果 。 需要两个直径直径的平面图的直径数( 但一般不够充分) 由两张直径直方平方平面的直径来转换为另一端平面的直径直径直方形平方, 。 也足够地显示我们的平面的平面的平方的平面结果。</s>