We study the secretary problem in which rank-ordered lists are generated by the Mallows model and the goal is to identify the highest ranked candidate through a sequential interview process which does not allow rejected candidates to be revisited. The main difference between our formulation and existing models is that, during the selection process, we are given a fixed number of questions to ask whether the current candidate is the highest-ranked or not. If the response is positive, the selection process terminates, otherwise, the search continues until a new potentially optimal candidate is identified. For the solution of our problem, we adopt a combinatorial method with new ideas and significant extensions compared to the work of Jones for the secretary problem with one selection. Our optimal interview strategy, as well as the expected number of candidates interviewed and expected number of queries used, can be determined exactly through the evaluation of well-defined recurrence relations. Specifically, if we are allowed to query $s-1$ times and to make a final selection without querying (thus, making $s$ selections in total) then the optimum scheme is characterized by $s$ thresholds that depend on the parameter $\theta$ of the Mallows distribution. These thresholds are independent from the maximal number of queries $s$.
翻译:我们研究的是马洛兹模式产生排名顺序名单的秘书问题,目标是通过顺序面试过程确定排名最高的候选人,不允许对被拒绝的候选人重新进行审查;我们拟订和现有模式之间的主要区别是,在甄选过程中,我们得到固定数量的问题,以询问目前的候选人是否排名最高;如果回答是肯定的,则甄选程序将终止,直到找到新的可能最佳的候选人为止;为了解决我们的问题,我们采用一种组合方法,与琼斯的工作相比,对秘书问题采用新想法和重大扩展,不允许对被否决的候选人进行重新审视;我们的最佳面试战略以及预期的受访候选人人数和预期的查询次数,可以通过对明确界定的重现关系进行评估来准确确定。具体地说,如果我们获准询问1美元,并在最后选择时不提出疑问(因此,总共要选择美元),那么,最佳办法的特点是以美元为门槛,这取决于Mallows分配的参数$/theta$。 这些阈值是独立的。