A graph $G$ is Hamiltonian-connected if there exists a Hamiltonian path between any two vertices of $G$. It is known that if $G$ is 2-connected then the graph $G^2$ is Hamiltonian-connected. In this paper we prove that the square of every self-complementary graph of order grater than 4 is Hamiltonian-connected. If $G$ is a $k$-critical graph, then we prove that the Mycielski graph $\mu(G)$ is $(k+1)$-critical graph. Jarnicki et al.[7] proved that for every Hamiltonian graph of odd order, the Mycielski graph $\mu(G)$ of $G$ is Hamiltonian-connected. They also pose a conjecture that if $G$ is Hamiltonian-connected and not $K_2$ then $\mu(G)$ is Hamiltonian-connected. In this paper we also prove this conjecture.
翻译:一张G$图与汉密尔顿相连接,如果在任何两个G$的顶点之间有一个汉密尔顿路径。已知如果G$是2G,那么G$是汉密尔顿相连接。在本文件中,我们证明每个自补的4美元线图的正方形与汉密尔顿相连接。如果G$是一K美元临界图,那么我们证明Mycielski图$\mu(G)是(k+1)$-临界图。Jarnicki等人[7]证明,对于每一个汉密尔顿奇图来说,Mycielski图$\mu(G)$G)是汉密尔顿相连接的。它们也构成一个假设,如果G$是汉密尔密尔顿相连接,而不是K$2美元,那么$\mu(G)是汉密尔顿相连接的。在这个文件中,我们也证明了这一推测。