We consider a best arm identification (BAI) problem for stochastic bandits with adversarial corruptions in the fixed-budget setting of $T$ steps. We design a novel randomized algorithm, Probabilistic Sequential Shrinking$(u)$ (PSS$(u)$), which is agnostic to the amount of corruptions. When the amount of corruptions per step (CPS) is below a threshold, {PSS}$(u)$ identifies the best arm or item with probability tending to $1$ as $T\rightarrow\infty$. Otherwise, the optimality gap of the identified item degrades gracefully with the CPS. We argue that such a bifurcation is necessary. In addition, we show that when the CPS is sufficiently large, no algorithm can achieve a BAI probability tending to $1$ as $T\rightarrow \infty$. In PSS$(u)$, the parameter $u$ serves to balance between the optimality gap and success probability. En route, the injection of randomization is shown to be essential to mitigate the impact of corruptions. Indeed, we show that PSS$(u)$ has a better performance than its deterministic analogue, the Successive Halving (SH) algorithm by Karnin et al. (2013). PSS$(2)$'s performance guarantee matches SH's when there is no corruption. Finally, we identify a term in the exponent of the failure probability of PSS$(u)$ that generalizes the common $H_2$ term for BAI under the fixed-budget setting.
翻译:我们认为,在固定预算($T$)的设置中,对有对抗性腐败的暴徒来说,最好的手臂识别(BAI)问题是最好的手臂识别(BAI)问题。我们设计了一种新的随机算法,即概率序列递减(u)美元(PSS$(u),这与腐败的程度是不可知的。当每一步(CPS)的腐败程度低于阈值时,{PSS}(u)美元确定最好的手臂或物品的概率为$T\rightrow\infty$。否则,所查明的项目的最佳性差会优于CPS。我们认为,这种分解是有必要的。此外,当CPS足够大的时候,任何算法都不可能达到每一步(CPS)的1美元概率($),而PSS(u)的值确定最佳差距和成功概率之间的平衡。在这条路线下,随机化的输入比CPSS公司总成本(x)更能稳定其业绩。