A P-matrix is a square matrix $X$ such that all principal submatrices of $X$ have positive determinant. Such matrices appear naturally in instances of the linear complementarity problem, where these are precisely the matrices for which the corresponding linear complementarity problem has a unique solution for any input vector. Testing whether or not a square matrix is a P-matrix is co-NP complete, so while it is possible to exhibit polynomially-sized witnesses for the fact that a matrix is not a P-matrix, it is believed that there is no efficient way to prove that a given matrix is a P-matrix. We will show that several well known witnesses for the fact that a matrix is not a P-matrix are computationally equivalent, so that we are able to convert between them in polynomial time, answering a question raised in arXiv:1811.03841 .
翻译:P-矩阵是一个平方矩阵x$X美元,因此所有主要次矩阵都具有积极的决定因素。这种矩阵自然地出现在线性互补问题中,正是在这些矩阵中,相应的线性互补问题对任何输入矢量都有独特的解决办法。 测试一个平方矩阵是否是一个P-矩阵是共同-NP是完整的,因此,虽然可以展示一个矩阵不是P-矩阵的多种族规模的证人,但相信没有有效的方式证明一个特定矩阵是P-矩阵。 我们将表明,几个众所周知的证人,证明一个矩阵不是P-矩阵的这一事实在计算上是等效的,因此我们能够在多民族时间转换它们,回答在arXiv:181.03841中提出的问题。