In a recently introduced coset guessing game, Alice plays against Bob and Charlie, aiming to meet a joint winning condition. Bob and Charlie can only communicate before the game starts to devise a joint strategy. The game we consider begins with Alice preparing a 2m-qubit quantum state based on a random selection of three parameters. She sends the first m qubits to Bob and the rest to Charlie and then reveals to them her choice for one of the parameters. Bob is supposed to guess one of the hidden parameters, Charlie the other, and they win if both guesses are correct. From previous work, we know that the probability of Bob's and Charlie's guesses being simultaneously correct goes to zero exponentially as m increases. We derive a tight upper bound on this probability and show how Bob and Charlie can achieve it. While developing the optimal strategy, we devised an encoding circuit using only CNOT and Hadamard gates, which could be relevant for building efficient CSS-coded systems. We found that the role of quantum information that Alice communicates to Bob and Charlie is to make their responses correlated rather than improve their individual (marginal) correct guessing rates.
翻译:在最近提出的陪集猜测游戏中,Alice与Bob和Charlie对抗,旨在满足联合获胜条件。Bob和Charlie只能在游戏开始前进行通信以制定联合策略。我们考虑的游戏开始时,Alice根据三个参数的随机选择制备一个2m量子比特的量子态。她将前m个量子比特发送给Bob,其余发送给Charlie,然后向他们揭示她选择的其中一个参数。Bob需要猜测一个隐藏参数,Charlie猜测另一个,若两者均猜对则获胜。根据先前研究可知,随着m增加,Bob和Charlie同时猜对的概率以指数形式趋近于零。我们推导了该概率的严格上界,并展示了Bob和Charlie达成该上界的方法。在开发最优策略过程中,我们设计了一种仅使用CNOT门和Hadamard门的编码电路,这可能对构建高效的CSS编码系统具有参考价值。我们发现,Alice传递给Bob和Charlie的量子信息的作用在于使他们的响应产生关联,而非提升各自(边缘)的正确猜测率。