This paper optimizes motion planning when there is a known risk that the road choice suggested by a Satnav (GPS) is not on a shortest path. At every branch node of a network Q, a Satnav (GPS) points to the arc leading to the destination, or home node, H - but only with a high known probability p. Always trusting the Satnav's suggestion may lead to an infinite cycle. If one wishes to reach H in least expected time, with what probability q=q(Q,p) should one trust the pointer (if not, one chooses randomly among the other arcs)? We call this the Faulty Satnav (GPS) Problem. We also consider versions where the trust probability q can depend on the degree of the current node and a `treasure hunt' where two searchers try to reach H first. The agent searching for H need not be a car, that is just a familiar example -- it could equally be a UAV receiving unreliable GPS information. This problem has its origin not in driver frustration but in the work of Fonio et al (2017) on ant navigation, where the pointers correspond to pheromone markers pointing to the nest. Neither the driver or ant will know the exact process by which a choice (arc) is suggested, which puts the problem into the domain of how much to trust an option suggested by AI.
翻译:本文优化了运动规划, 当已知的风险是 Satnav (GPS) 所建议的道路选择不是在最短的路径上。 在网络 Q 的每一个分支节点上, Satnav (GPS) 指向通往目的地或家节点的弧弧, H - 但仅指高度已知的概率 。 始终信任 Satnav 的建议可能会导致一个无限的循环。 如果有人希望在最不预期的时间内到达H, 以什么概率 q=q( Q, p) 来信任指针( 如果不是, 则在其他弧圈之间随机选择 )? 我们称之为 Fauty Satnav (GPS) 问题。 我们还会考虑信任概率q 可以取决于当前节点的程度和“ 追踪” 的版本, 其中两位搜索者首先试图到达H。 搜索的代理器不需要一辆汽车, 仅仅是一个熟悉的例子 -- 这个问题同样可能是接收不可靠的全球定位系统信息的UAV。 这个问题的根源不是驱动器的挫折感, 而是在驱动器和驱动器 AL1 (2017) 的轨道上显示一个方向。