The area of computing with uncertainty considers problems where some information about the input elements is uncertain, but can be obtained using queries. For example, instead of the weight of an element, we may be given an interval that is guaranteed to contain the weight, and a query can be performed to reveal the weight. While previous work has considered models where queries are asked either sequentially (adaptive model) or all at once (non-adaptive model), and the goal is to minimize the number of queries that are needed to solve the given problem, we propose and study a new model where $k$ queries can be made in parallel in each round, and the goal is to minimize the number of query rounds. We use competitive analysis and present upper and lower bounds on the number of query rounds required by any algorithm in comparison with the optimal number of query rounds. Given a set of uncertain elements and a family of $m$ subsets of that set, we present an algorithm for determining the value of the minimum of each of the subsets that requires at most $(2+\varepsilon) \cdot \mathrm{opt}_k+\mathrm{O}\left(\frac{1}{\varepsilon} \cdot \lg m\right)$ rounds for every $0<\varepsilon<1$, where $\mathrm{opt}_k$ is the optimal number of rounds, as well as nearly matching lower bounds. For the problem of determining the $i$-th smallest value and identifying all elements with that value in a set of uncertain elements, we give a $2$-round-competitive algorithm. We also show that the problem of sorting a family of sets of uncertain elements admits a $2$-round-competitive algorithm and this is the best possible.
翻译:具有不确定性的计算领域会考虑关于输入元素的某些信息不确定但可以通过查询获得的问题。 例如, 与元素的重量相比, 我们可能会得到一个保证包含重量的间隔, 并可以进行查询以显示重量。 虽然先前的工作已经考虑过按顺序( 适应模式) 或一次性( 非适应模式) 询问的模型, 目标是尽量减少解决给定问题所需的查询次数, 我们提议并研究一个新的模式, 即每回合可以同时查询美元, 并且目标是将查询元素的数量减少到最小值。 我们使用竞争分析, 并在任何算法要求的轮数中显示上下限值, 与最佳轮数相比。 鉴于一组不确定元素和该组的美元子集, 我们提出一个算法, 确定每个子集的最小值, 最多需要 $ ( ⁇ vareepsilllll) 最低值, 最低值, 最低值( we stock) 和最低限值 美元 美元 美元 ; 最低值 最低值=\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\